Question

Hydrogen selenide (H,Se) reacts with water according to the following equation.
H,Se + H20 → SeHT + H30+
Identify the acid, base, conjugate acid, and conjugate base in this reaction
(2 points)

Acid
Base
Conjugate acid
Conjugate base
H30+
H,Se

Answer 1

In the reaction provided:

\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}_3^+ + \text{H}_3\text{O}^+ \]

We can identify the components as follows:

- **Acid**: \[\text{H}_2\text{Se}\] (donates a proton, H\(^+\), to water)
- **Base**: \[\text{H}_2\text{O}\] (accepts a proton to form H\(_3\)O\(^+\))
- **Conjugate Acid**: \[\text{SeH}_3^+\] (formed from the base \(\text{H}_2\text{Se}\) after it donates a proton)
- **Conjugate Base**: \[\text{H}_2\text{O}\] (after it donates a proton, it forms H\(_3\)O\(^+\))

So, while you've provided H\(_3\)O\(^+\) as an option, it's actually the conjugate acid of water after it accepts a proton. Therefore, for clarity:

- Acid: \[\text{H}_2\text{Se}\]
- Base: \[\text{H}_2\text{O}\]
- Conjugate Acid: \[\text{SeH}_3^+\]
- Conjugate Base: None directly listed; however, \[\text{H}_2\text{O}\] could be considered in a different context.

In this context, typically, we consider \[\text{SeH}_3^+\] as the conjugate acid of \(\text{H}_2\text{Se}\) after it donates a proton.