Question
Hydrogen selenide (H2Se) reacts with water according to the following equation. H2Se + H2O → SeH– + H3O+ Identify the acid, base, conjugate acid, and conjugate base in this reaction (2 points) Acid Base Conjugate acid Conjugate base H2Se H3O+
Answers
GPT-4o mini
In the reaction you provided:
\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]
we can identify the following:
- **Acid:** \( \text{H}_2\text{Se} \) (because it donates a proton)
- **Base:** \( \text{H}_2\text{O} \) (because it accepts a proton)
- **Conjugate Acid:** \( \text{H}_3\text{O}^+ \) (it's formed when water accepts a proton)
- **Conjugate Base:** \( \text{SeH}^- \) (it's formed when \( \text{H}_2\text{Se} \) donates a proton)
So the final identification is:
- **Acid:** \( \text{H}_2\text{Se} \)
- **Base:** \( \text{H}_2\text{O} \)
- **Conjugate Acid:** \( \text{H}_3\text{O}^+ \)
- **Conjugate Base:** \( \text{SeH}^- \)
\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]
we can identify the following:
- **Acid:** \( \text{H}_2\text{Se} \) (because it donates a proton)
- **Base:** \( \text{H}_2\text{O} \) (because it accepts a proton)
- **Conjugate Acid:** \( \text{H}_3\text{O}^+ \) (it's formed when water accepts a proton)
- **Conjugate Base:** \( \text{SeH}^- \) (it's formed when \( \text{H}_2\text{Se} \) donates a proton)
So the final identification is:
- **Acid:** \( \text{H}_2\text{Se} \)
- **Base:** \( \text{H}_2\text{O} \)
- **Conjugate Acid:** \( \text{H}_3\text{O}^+ \)
- **Conjugate Base:** \( \text{SeH}^- \)