Asked by Happy Face

A car going at 30 m/s undergoes acceleration of 2 m/s^2 for 4 sec. What is its final speed? How far did it travel while it was accelerating?

acceleration=the change in velocity/(divided by) the change in time

plz help thx
Answered by Anonymous
30m/s at 0 sec
30m/s + 2m/s (at 1 sec)
30m/s + 2m/s + 2m/s (at 2 sec)
etc.
Answered by Anonymous
The distance = (1/2)*(acceleration)*(time)^2 + (initial velocity)*(time).
Answered by Happy Face
what is the distance?
i got 184 is that correct?
the answer on my worksheet says 136...is this wrong or right?
PLZ HELP!!
Answered by TutorCat
136 is correct. Check your work.
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