Question

If 45L of methane undergoes complete combustion at 1.1atm and 95 ° F how many grams of each product are formed?
bobpursley
CH4 + 2O2 >> CO2 + 2H2O
moles methane:
n=PV/RT go through that, convert temps to Kelvins first. Use the correct R.
then, moles CO2=n, moles water vapor=2n

convert each to grams: mass=moles*molmasseach

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