Asked by Anonymous
A car going at 30 m/s undergoes an acceleration of 2m/s squared for 4 seconds. What is it's final speed? How far did it travel while it was accelerating?
Answers
Answered by
drwls
V(t) = Vo + a*t
X(t) = Vo*t + (1/2)a*t^2
Learn them and use them.
t = 4. Vo = 30 m/s a = 2 m/s^2
BTW, drop the apostrophe in it's.
X(t) = Vo*t + (1/2)a*t^2
Learn them and use them.
t = 4. Vo = 30 m/s a = 2 m/s^2
BTW, drop the apostrophe in it's.
Answered by
Faith
2 m/s^2=?-30m/s^2/4s
?-30=4*2
?-30=8
?=8+30=38
1st speed=38m/s
?-30=4*2
?-30=8
?=8+30=38
1st speed=38m/s
Answered by
Bob
A certain airplane has an acceleration of 15.0 m/s2
How fast will it be moving2.5s after it starts down runway
How far down runway during the 2.5s
How fast will it be moving2.5s after it starts down runway
How far down runway during the 2.5s
Answered by
Big House
The first speed is 38m/s
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