Question
A substance undergoes a first-order decomposition. After 40.0 min at 500 degrees C, only 12.5% of the original sample remains. What is the half-life of the decomposition? If the original sample weighted 243 g, how much would remain after 2 hours?
Answers
College Hacker
).5^n = 0.125
n = 3
t 1/2 = 40 mins / 3
t 1/2 = 13.3 mins
Hope that helps
n = 3
t 1/2 = 40 mins / 3
t 1/2 = 13.3 mins
Hope that helps
College Hacker
n * t1/2 = mass/(2^n)
n * t1/2 = 2 hrs = 120 mins
n = 120/13.3
n = 9.02 (n = number of half-cycles)
remaining mass = 243/(2^9.02)
= 0.467g
0.467g is remaining after 2 hrs
n * t1/2 = 2 hrs = 120 mins
n = 120/13.3
n = 9.02 (n = number of half-cycles)
remaining mass = 243/(2^9.02)
= 0.467g
0.467g is remaining after 2 hrs
Writeacher
Is Bob going to trust someone who calls himself "College Hacker"? Hmmm!
College Hacker
It's up to Bob. If you find anything wrong with the solution, please correct it :)