Asked by Blanca
A car going 50 m/s undergoes an acceleration of 2 m/s^2 for 6 seconds what is the final velocity ? How far did it travel while it was accelerating?
Answers
Answered by
Steve
well v increased by 2 m/s every second, so it wound up at 50+2*6 = 62 m/s
since the position is
s(t) = 50t + t^2
just figure s(6)
since the position is
s(t) = 50t + t^2
just figure s(6)
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