Question

A car going 50 m/s undergoes an acceleration of 2 m/s^2 for 6 seconds what is the final velocity ? How far did it travel while it was accelerating?

Answer 1

well v increased by 2 m/s every second, so it wound up at 50+2*6 = 62 m/s

since the position is

s(t) = 50t + t^2
just figure s(6)