Asked by Shadow
Determine the mole fraction of acetone in a solution prepared by adding 0.456 kg of (CH3)2CO to 0.899 L of C4H8O.
Molar Mass (g/mol)
(CH3)2CO 58.05
C4H8O 72.12
Density (g/ml):
(CH3)2CO 0.7899
C4H8O 0.8892
Name/Formula:
acetone
(CH3)2CO
tetrahydrofuran
C4H8O
I need help!!
Molar Mass (g/mol)
(CH3)2CO 58.05
C4H8O 72.12
Density (g/ml):
(CH3)2CO 0.7899
C4H8O 0.8892
Name/Formula:
acetone
(CH3)2CO
tetrahydrofuran
C4H8O
I need help!!
Answers
Answered by
DrBob222
moles fraction acetone = moles aetone/(moles acetone + moles THF).
Convert g acetone to moles.
Convert L THF to grams and to moles.
Substitute into the above mole fraction formula.
Convert g acetone to moles.
Convert L THF to grams and to moles.
Substitute into the above mole fraction formula.
Answered by
bobpursley
figure the moles of acetone by 256/58.05
next, figure the moles of Ch4H8O
mass= 899ml*.8992g/ml
moles= mass/mole mass
Mole fraction acetone = molesacetone/total moles
next, figure the moles of Ch4H8O
mass= 899ml*.8992g/ml
moles= mass/mole mass
Mole fraction acetone = molesacetone/total moles
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