Question
Determine The Mole Fraction Of Substances In Solution Containing 36g of water and 46g of glaycerine C3H5(OH)3.
Answers
Get first the number of moles (n) of each species. To get the moles, divide the mass by the molar mass. To get the molar mass, get a periodic table and add the individual mass of the elements in the chemical formula.
H2O (water): 2*1 + 1*16 = 18 g/mol
C3H8O3 (glycerine): 3*12 + 8*1 + 3*16 = 92 g/mol
Therefore,
n,H2O = 36 / 18 = 2 mol H2O
n,C3H8O3 = 46 / 92 = 0.5 mol C3H8O3
To get the molar fraction of each, get the total moles, and divide each moles by the total:
Total moles = 2.5 moles
molar fraction, H2O = 2/2.5 = 0.8
molar fraction, C3H8O3 = 0.5/2.5 = 0.2
Hope this helps :3
H2O (water): 2*1 + 1*16 = 18 g/mol
C3H8O3 (glycerine): 3*12 + 8*1 + 3*16 = 92 g/mol
Therefore,
n,H2O = 36 / 18 = 2 mol H2O
n,C3H8O3 = 46 / 92 = 0.5 mol C3H8O3
To get the molar fraction of each, get the total moles, and divide each moles by the total:
Total moles = 2.5 moles
molar fraction, H2O = 2/2.5 = 0.8
molar fraction, C3H8O3 = 0.5/2.5 = 0.2
Hope this helps :3
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