Asked by Devon
What is the mole fraction of ethanol, C2H5OH, in an aqueous solution that is 50.0% ethanol by mass?
Answers
Answered by
bobpursley
assume 1000g
molesEthanol=500/46
molesH2O=500/18
mole fractionEthanol=moleEthanol/total moles
= (500/46)/(500/46+500/18)
= 1/(1+46/18)
molesEthanol=500/46
molesH2O=500/18
mole fractionEthanol=moleEthanol/total moles
= (500/46)/(500/46+500/18)
= 1/(1+46/18)
Answered by
Anonymous
Calculate yourself .I hope u all have got brain...Right.!!
Answered by
Gabby
0.282
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