Asked by Anonymous
What is the mole fraction of urea, CO(NH2)2, in a solution prepared by dissolving 6.6 g of urea in 30.2 g of methanol, CH3OH?
Answers
Answered by
DrBob222
molar mass urea = 60
molar mass methanol = 32
mols urea = 6.6/60 = 0,11
mols methanol = 30.2/32 = 0.944
Total mols = 0.11 + 0.944 = 1.054
Xurea = moles urea/total moles = ?
Xmethanol = mols methanol/total moles - ?
Check my arithmetic.
molar mass methanol = 32
mols urea = 6.6/60 = 0,11
mols methanol = 30.2/32 = 0.944
Total mols = 0.11 + 0.944 = 1.054
Xurea = moles urea/total moles = ?
Xmethanol = mols methanol/total moles - ?
Check my arithmetic.
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