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A solution containing silver (I) ion (an oxidizing agent) is mixed with a solution containing iron (II) ion (a reducing agent)....Asked by anonymous
A solution containing silver (I) ion (an oxidizing agent) is mixed with a solution containing iron (II) ion (a reducing agent).
a. What is the balanced equation?
b. If the contents of the reaction mixture described above are filtered, what substances, if any, would remain on the filter paper?
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For A, I can't think of any other product other than AgFe, which makes no sense.
Help? Thanks!
a. What is the balanced equation?
b. If the contents of the reaction mixture described above are filtered, what substances, if any, would remain on the filter paper?
---
For A, I can't think of any other product other than AgFe, which makes no sense.
Help? Thanks!
Answers
Answered by
GK
The oxidizing agent, Ag+, gained an electron and is reduced to Ag(s).
The reducing agent loses an electron and is oxidized from Fe^2+ to Fe^3+:
Ag^+(aq) + Fe^2+(aq) --> Ag(s) + Fe^3+(aq)