Asked by ULIA

How ml silver nitrate solution (0.05 mol / l) K = 1.0000 consumed for titration of sodium chloride, 0.0500 g. MW Sodium chloride 58.44.

Answers

Answered by DrBob222
Ag^+ + Cl^- ==> AgCl
mols NaCl = 0.05g/molar mass = ?
mols AgNO3 = mols NaCl
M AgNO3 = mols AgNO3/L AgNO3
You know M and mols, solve for L AgNO3 and convert to mL.
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