Asked by Swagato
A solution is 36% silver nitrate (AgNO3) by mass. The density of this solution is 1.44
g/mL. The formula weight of AgNO3 is 170
g/mol. Calculate the molality of AgNO3 in
this solution.
g/mL. The formula weight of AgNO3 is 170
g/mol. Calculate the molality of AgNO3 in
this solution.
Answers
Answered by
DrBob222
36% AgNO3 means 36 g AgNO3/100 g solution.
36 g = 36/170 moles = ??
100 g solution = volume x density. Calculate volume. Then M = moles/L soln.
36 g = 36/170 moles = ??
100 g solution = volume x density. Calculate volume. Then M = moles/L soln.