Asked by Angel
When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 5.0 M HCI is required to react completely with 3.00 g of magnesium?
Answers
Answered by
GK
The Chemical reaction is:
Mg + 2HCl --> MgCl2 + H2
1) Divide the grams of Mg by the atomic mass of Mg to get moles of Mg.
2) Moles of HCl = (2)(moles of Mg)
3) Moles of HCl = (V)(5.0 mol/L)
or
Volume of HCl = (mol. HCl) / (5.0 mol/L)
---------
NOTE: The volume of HCl will be in liters
Mg + 2HCl --> MgCl2 + H2
1) Divide the grams of Mg by the atomic mass of Mg to get moles of Mg.
2) Moles of HCl = (2)(moles of Mg)
3) Moles of HCl = (V)(5.0 mol/L)
or
Volume of HCl = (mol. HCl) / (5.0 mol/L)
---------
NOTE: The volume of HCl will be in liters
Answered by
Anonymous
If 5.00 g of manganese (IV) oxide reacts with 25.0 mL of 6.00 M hydrochloric acid, what is the calculated mass of chlorine gas produced?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.