Question
Zinc reacts with hydrochloric acid according to the reaction equation:
Zn(s)+2HCl(aq)->ZnCl2(aq)+H2(g)
How many milliliters of 4.50M HCl1(aq) are required to react with 8.25g of an ore containing 30.0% Zn(s) by mass?
Zn(s)+2HCl(aq)->ZnCl2(aq)+H2(g)
How many milliliters of 4.50M HCl1(aq) are required to react with 8.25g of an ore containing 30.0% Zn(s) by mass?
Answers
bobpursley
convert .30*8.25g to moles Zn
You need twice that number of moles of HCL
molesneeded=litersacid*4.5
conver that to ml.
You need twice that number of moles of HCL
molesneeded=litersacid*4.5
conver that to ml.
5849
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