Question

Zinc reacts with hydrochloric acid according to the reaction equation...
Zn (s) + 2HCl (aq) ---> ZnCl2 (aq) + H2 (g)

How many milliliters of 5.00 M HCl (aq) are required to react with 5.55 g of Zn (s)??

Answer 1

mols Zn = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Zn to mols HCl.
Then M HCl = mols HCl/L HCl. You know mols and M, solve for L and convert to mL.

Answer 2

.849mL?

Answer 3

It's 33.9mL!!!!!!
:) Thanks

Answer 4

I obtained 33.96 which I would round to 34.0 to three significant figures. I suspect you just threw the 6 in 33.96 away without thinking about it.