Asked by Anon
When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 1.0 M HCl is required to react completely with 4.00 g of magnesium
i did 4.00g x (mol/24.31 g Mg) x (2 mol HCl/1 mol Mg) x (L/!.0 mol HCl) = .329 L
why is this wrong?
i did 4.00g x (mol/24.31 g Mg) x (2 mol HCl/1 mol Mg) x (L/!.0 mol HCl) = .329 L
why is this wrong?
Answers
Answered by
DrBob222
It looks ok to me, too. Perhaps the answer should be in mL and not L. Check the problem and your typing. Make sure all of the numbers and units agree.
Answered by
bobpursley
I don't see an error.
Answered by
DrBob222
I just noticed that the molarity of the HCl is 1.0 M; therrefore, you have only two significant figures. Thus the answer should be reported as 0.329 = 0.33 L tp 2 s.f. That may be the problem.
Answered by
Anon
thanks that worked