Asked by Urgent Please help!
How do i differentiate cos(3/x) or sin(4/x)? Please help!
Answers
Answered by
bobpursley
f'(x)=d f(u)/dx= f'(u) du/dx
d cos(3/x)= -sin(3/x) d(3/x)/dx
=-sin(3/x) * (-3/x^2)
check my thinking.
d cos(3/x)= -sin(3/x) d(3/x)/dx
=-sin(3/x) * (-3/x^2)
check my thinking.
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