To solve the system of equations using substitution, we can solve one equation for one variable and substitute it into the other equation.
Let's solve the second equation for x:
-x + y = 11
x = y + 11
Now substitute this value of x into the first equation:
3x + 2y = 12
3(y + 11) + 2y = 12
3y + 33 + 2y = 12
5y + 33 = 12
5y = -21
y = -21/5
Now substitute this value of y back into x = y + 11:
x = (-21/5) + 11
x = (-21 + 55)/5
x = 34/5
Therefore, the solution to the system of equations is (34/5, -21/5).
Solve the system of linear equations given below using substitution or elimination. 3x+2y=12 −x+y=11 (1 point) (, )
1 answer