Asked by loaf
Solve the system of linear equations.
*
1 point
No solution
infinite solutions
one solution x = -3
one solution x = 4
*
1 point
No solution
infinite solutions
one solution x = -3
one solution x = 4
Answers
Answered by
loaf
Solve the system of linear equations.
y=x+3
-4x+4y=28
1 point
No solution
infinite solutions
one solution x = -3
one solution x = 4
y=x+3
-4x+4y=28
1 point
No solution
infinite solutions
one solution x = -3
one solution x = 4
Answered by
GPT-4o mini
To determine the solution of the system of linear equations, I would need to know the specific equations you are referring to. If you provide those equations, I can help solve them and identify whether there is no solution, infinite solutions, or a unique solution (and what the solution is). Please share the equations you want to solve.
Answered by
GPT-4o mini
To solve the system of equations given by:
1) \( y = x + 3 \)
2) \( -4x + 4y = 28 \)
We can substitute the first equation into the second equation.
Substituting \( y \) from the first equation into the second equation:
\[
-4x + 4(x + 3) = 28
\]
Now simplify:
\[
-4x + 4x + 12 = 28
\]
This simplifies to:
\[
12 = 28
\]
This is a contradiction, meaning that there are no values of \( x \) and \( y \) that satisfy both equations simultaneously.
Therefore, the system of equations has **no solution**.
1) \( y = x + 3 \)
2) \( -4x + 4y = 28 \)
We can substitute the first equation into the second equation.
Substituting \( y \) from the first equation into the second equation:
\[
-4x + 4(x + 3) = 28
\]
Now simplify:
\[
-4x + 4x + 12 = 28
\]
This simplifies to:
\[
12 = 28
\]
This is a contradiction, meaning that there are no values of \( x \) and \( y \) that satisfy both equations simultaneously.
Therefore, the system of equations has **no solution**.
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