Asked by sandra
                solve the system of linear equations
2x+2y=1
3x-y=6
thanks
            
        2x+2y=1
3x-y=6
thanks
Answers
                    Answered by
            Joe
            
    2x+2y=1
This one is obvious. Just divide the coefficients by each other, and take any inequalities and subtract them by themselves.
3x-y=6
This one is a bit tougher. First, you need to square everything. Then add 4, subtract 7, and take the square root of it all. It may not seem right, but it IS fairly complex.
    
This one is obvious. Just divide the coefficients by each other, and take any inequalities and subtract them by themselves.
3x-y=6
This one is a bit tougher. First, you need to square everything. Then add 4, subtract 7, and take the square root of it all. It may not seem right, but it IS fairly complex.
                    Answered by
            Anonymous
            
    2x+2y=1
6x-2y=12
-4x=-11
x= 11/4
2(11/4)+2y=1
1-22/4=2y
-18/4=2y
-18/8=y
    
6x-2y=12
-4x=-11
x= 11/4
2(11/4)+2y=1
1-22/4=2y
-18/4=2y
-18/8=y
                    Answered by
            Reiny
            
    1st equation ---> 2x + 2y = 1
2nd equation times 2 ---> 6x - 2y = 12
add them
8x = 13
x = 13/8
sub into 1st:
2(13/8+ 2y = 1
2y = 1 - 13/4
2y = -9/4
y = -9/8
x = 13/8 , y = -9/8
    
2nd equation times 2 ---> 6x - 2y = 12
add them
8x = 13
x = 13/8
sub into 1st:
2(13/8+ 2y = 1
2y = 1 - 13/4
2y = -9/4
y = -9/8
x = 13/8 , y = -9/8
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