Question
solve the system of linear equations
2x+2y=1
3x-y=6
thanks
2x+2y=1
3x-y=6
thanks
Answers
Joe
2x+2y=1
This one is obvious. Just divide the coefficients by each other, and take any inequalities and subtract them by themselves.
3x-y=6
This one is a bit tougher. First, you need to square everything. Then add 4, subtract 7, and take the square root of it all. It may not seem right, but it IS fairly complex.
This one is obvious. Just divide the coefficients by each other, and take any inequalities and subtract them by themselves.
3x-y=6
This one is a bit tougher. First, you need to square everything. Then add 4, subtract 7, and take the square root of it all. It may not seem right, but it IS fairly complex.
Anonymous
2x+2y=1
6x-2y=12
-4x=-11
x= 11/4
2(11/4)+2y=1
1-22/4=2y
-18/4=2y
-18/8=y
6x-2y=12
-4x=-11
x= 11/4
2(11/4)+2y=1
1-22/4=2y
-18/4=2y
-18/8=y
Reiny
1st equation ---> 2x + 2y = 1
2nd equation times 2 ---> 6x - 2y = 12
add them
8x = 13
x = 13/8
sub into 1st:
2(13/8+ 2y = 1
2y = 1 - 13/4
2y = -9/4
y = -9/8
x = 13/8 , y = -9/8
2nd equation times 2 ---> 6x - 2y = 12
add them
8x = 13
x = 13/8
sub into 1st:
2(13/8+ 2y = 1
2y = 1 - 13/4
2y = -9/4
y = -9/8
x = 13/8 , y = -9/8