Question

Solve by Graphing
x^2+2x-3=0
9 questions
quadratic systems quiz part 1
unit 5 lesson 8
please post all answers

Answer 1

x^2+2x-3=0
(x+3)(x-1) = 0
x=-3 or x=1

on a number line circle the -3 and the 1

Answer 2

I have just finished and here are the answers
1:c (1, -3)
2:b (6.2, 9.1)
3:a (1-7i)
4:d (no)
5:a (0,3)
6:a (-3/4i,3/4i)
7:c (-4,0 -1,3)
8:a (tiny grey)
9:b (5i)

Answer 3

Step by step solution

Factoring this quadratic equation.
_____________
Remark:
- x + 3 x = 2 x
_____________

x² + 2 x - 3 = x² - x + 3 x - 3 =

( x² - x ) + ( 3 x - 3 )=

x ( x - 1 ) + 3 ( x - 1) =

( x - 1 ) ( x + 3 )

x² + 2 x - 3 = 0

is same as

( x - 1 ) ( x + 3 ) = 0

The equation will be equal to zero when the expressions in parentheses are equal to zero.

First solution.

x - 1 = 0

Add 1 to both sides.

x = 1

Second solution.

x + 3 = 0

Subtract 3 to both sides.

x = - 3

The solutions are:

x = - 3 and x = 1

Answer 4

Answrr is c

( 1, - 3 )

Answer 5

bramboy is correct
100%