graph
y = x^2 + 16
You will see a parabola opening upwards with vertex at (0,16)
"Solving" an equation is the same as finding the x-intercepts of the corresponding function.
It should be obvious that the graph cannot cross the x-axis.
Therefore there is no solution in the set of real numbers.
x^2 + 16=0
Solve by graphing
1 answer