Asked by princess
what volume of 0.1mol/dm3 hydrochloric acid would be required to react completely with 1.50g of calciumtrioxocarbonate (4) salt.
Answers
Answered by
oobleck
If your reaction is
CaCO3 + 2HCl → CaCl2 + H2O + CO2
then since
1.5g CaCO3 = 0.015 moles
you need 0.03 moles HCl = 0.3L of 0.1M HCl
CaCO3 + 2HCl → CaCl2 + H2O + CO2
then since
1.5g CaCO3 = 0.015 moles
you need 0.03 moles HCl = 0.3L of 0.1M HCl
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.