Asked by Vanessa Ozuna
When 1mol of a gas burns at constant pressure, it produces 2430J of heat and does 5kJ of work.
Calculate change in H, q, and in kJ?
Calculate change in H, q, and in kJ?
Answers
Answered by
DrBob222
Re-read your post. Did you omit calculating dE?
2430 J and it is exothermic. q = -2430J so dH is -2430 J.
It does 5,000 J work so work - 5000 J.
dE = q + w. dE will be in J.
Convert to kJ and convert the other so to kJ.
2430 J and it is exothermic. q = -2430J so dH is -2430 J.
It does 5,000 J work so work - 5000 J.
dE = q + w. dE will be in J.
Convert to kJ and convert the other so to kJ.
Answered by
Vanessa Ozuna
Thank you so much! on dE i get 2.57 but it is telling me it is wrong?
Answered by
Vanessa Ozuna
never mind I got it (:
Answered by
DrBob222
Both are negative. Why did you subtract?
dE = -2.43-5.00 = -7.43 kJ
dE = -2.43-5.00 = -7.43 kJ
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