Question

When 1mol of a gas burns at constant pressure, it produces 2430J of heat and does 5kJ of work.

Calculate change in H, q, and in kJ?

Answer 1

Re-read your post. Did you omit calculating dE?
2430 J and it is exothermic. q = -2430J so dH is -2430 J.
It does 5,000 J work so work - 5000 J.
dE = q + w. dE will be in J.
Convert to kJ and convert the other so to kJ.

Answer 2

Thank you so much! on dE i get 2.57 but it is telling me it is wrong?

Answer 3

never mind I got it (:

Answer 4

Both are negative. Why did you subtract?
dE = -2.43-5.00 = -7.43 kJ