Asked by jonah
25cm3 of a solution of 0.1mol dm-3 NaoH reacts with 50cm3 of a solution of hydrochloric acid.What is the molarity of the acid
Answers
Answered by
DrBob222
Write the equation and balance it.
HCl + NaOH ==> NaCl + H2O
How many moles NaOH were used? moles = M x L = ??
Using the coefficients in the balanced equation, convert moles NaOH to moles HCl. You can see that it is a 1:1 ratio of NaOH to HCl; therefore, moles NaOH = moles HCl.
Then M HCl = moles HCl/L HCl. You know mole and L, solve for M.
HCl + NaOH ==> NaCl + H2O
How many moles NaOH were used? moles = M x L = ??
Using the coefficients in the balanced equation, convert moles NaOH to moles HCl. You can see that it is a 1:1 ratio of NaOH to HCl; therefore, moles NaOH = moles HCl.
Then M HCl = moles HCl/L HCl. You know mole and L, solve for M.
Answered by
claire
is there any way i can see an answer for this.. i have it as an a level chemistry question and im either having a mental block... or totallyyy don't get it ?
Answered by
claire
this does not give the answer
Answered by
mustaphe mubarik abdikarin
34
Answered by
Favour or elvice
25cm3 of 1.5 solution of Nacl are added to 50cm3 of 3m Nacl. The molar concentration of the resulting solution is_
Answered by
David
0.05m/l
Answered by
Salani S
C(a)×V(a)=c(b)xv(b)
0.025dm-3x0.1mol=0.050dm-3x zmol
0.00025=0.050z
2.5/50=z
0.05mols/50cm-³
0.025dm-3x0.1mol=0.050dm-3x zmol
0.00025=0.050z
2.5/50=z
0.05mols/50cm-³
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