Asked by tinashe
25cm3 of a solution of NaOH required 28cm3 of 1.0mol/dm3 H2SO4 to neutralise it:
a) write an equation for the reaction.
b) how many molesof H2SO4 were needed?
c) how many moles of NaOH were thus nuetralised?
a) write an equation for the reaction.
b) how many molesof H2SO4 were needed?
c) how many moles of NaOH were thus nuetralised?
Answers
Answered by
DrBob222
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
I think for (b) you means how many mols H2SO4 were used. All of ot was meeded.
mols H2SO4 = M x L = ?
(c) Using the coefficients in the balanced equation, convert mols H2SO4 you had to mols NaOH neutralized.
(d) usually these problems want you to calculate the M of the NaOH.
That's M NaOH = mols NaOH/L NaOH
I think for (b) you means how many mols H2SO4 were used. All of ot was meeded.
mols H2SO4 = M x L = ?
(c) Using the coefficients in the balanced equation, convert mols H2SO4 you had to mols NaOH neutralized.
(d) usually these problems want you to calculate the M of the NaOH.
That's M NaOH = mols NaOH/L NaOH