Mixture of 0.1mol of NO,0.5mol of H2 and 0.1 mol of water is placed in a 1L vessel at 300K , at equilibrium the concentration of No is 0.06M. Calculate the concentration of N, H, and water.the equation is 2NO + 2H2 gives 2No+2H2O

Answer 1

Initial concentration:
(NO) = 0.1mol/1L = 0.1 M
(H2) = 0.5 mol/1L = 0.5 M
(H2O) = 0.1 mol/1L = 0.1 M

I don't believe the equation is correct. Please check your post. What is No?