Asked by Jack
What volume of 1.34 mol/L hydrochloric acid, HCI, is expected to react completely with 6.89 g of calcium?
Answers
Answered by
DrBob222
Ca + 2HCl --> CaCl2 + H2
mols Ca = grams/atomic mass
mols HCl = twice that since 1 mol Ca = 2 mols HCl
Then M HCl = mols HCl/L HCl and this can be arranged to L HCl = mols HCl/M HCl which let's you solve for L HCl.
mols Ca = grams/atomic mass
mols HCl = twice that since 1 mol Ca = 2 mols HCl
Then M HCl = mols HCl/L HCl and this can be arranged to L HCl = mols HCl/M HCl which let's you solve for L HCl.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.