Asked by anon
A rubber stopper with a mass of 50.0 g attached to a string is being rotated in a vertical circle with a radius of 0.72 m at a constant speed of 7.3 m/s. (/2)
What is the tension in the string when the stopper is at the top of the circle?
What is the tension in the string when the stopper is at the bottom of the circle.
What is the tension in the string when the stopper is at the top of the circle?
What is the tension in the string when the stopper is at the bottom of the circle.
Answers
Answered by
Anonymous
weight down = m g
tension due to centipedal acceleration = m v^2/R
at top T = m (v^2/R - g)
at bottom T = m (v^2/R + g)
tension due to centipedal acceleration = m v^2/R
at top T = m (v^2/R - g)
at bottom T = m (v^2/R + g)
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