Asked by Rosie

A 0.025kg rubber stopper is swung in a horizontal circle by a 0.95 meter threat that makes 25 revolutions every 15 minutes. a) what is the stoppers speed? b) what is the acceleration? c) what is the value of the centripetal force?

Answers

Answered by Rosie
sorry not minutes but 15 seconds
Answered by Damon
T = 15/25 = .6 second

C = 2 pi R = 2 * 3.14 * .95 = 5.97 meter

a) v = C/T = 9.94 m/s

b) v^2/R = 9.94^2/.95 = 104 m/s^2
wow, 10 g

c) F = m a = .025*104 = 2.6 Newtons

Answered by Rosie
thank you for your help
Answered by Damon
You are welcome.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions