Asked by Punani
A 0.013 kg rubber stopper attached to a 0.93 m string is swung in a circle. If the tension in the string is 0.70 N, what is the period of the stopper's revolution?
Answers
Answered by
Damon
Ac = v^2/r
so
.7 = .013 v^2/.93
solve for v
we know r
time = distance / speed = 2 pi r/v
so
.7 = .013 v^2/.93
solve for v
we know r
time = distance / speed = 2 pi r/v
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