Question
A 0.020 rubber stopper is swung in a horizontal circle by 0.80 cm thread that makes 30.0 revolution every 20 seconds.
a.) what is the stopper's speed?
T=?
v=(2pi(r))/T
a.) what is the stopper's speed?
T=?
v=(2pi(r))/T
Answers
Roy
T=1.5 s?
MathMate
T (period)
= time/rev
= 20 sec/ 30 rev
= 2/3 sec/rev
ω(angular speed)
=30 rev/20 seconds
=30/20 rev / sec
=30/20*2π radians / s
Velocity
=rω
=0.008m*ω m/s
= time/rev
= 20 sec/ 30 rev
= 2/3 sec/rev
ω(angular speed)
=30 rev/20 seconds
=30/20 rev / sec
=30/20*2π radians / s
Velocity
=rω
=0.008m*ω m/s