Asked by Chaz

A 3.8 kg ball is swung in a horizontal circle at the end of a 1.5 meter rope. If the tension in the rope is kept constant at 79 N, what is the period of rotation, T?
Answered by bobpursley
Well, ignoring gravity (gravity makes the ball swing downward, the rope makes an angle, which changes the radius of rotation), then

tension= massball*v^2/r=m(2PIr/T)^2 /r

do the algebra, and solve for Period T.

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