Question
A rubber ball of mass 0.12 kg is held at a height of 2.5 m above the ground, then released.
Calculate the velocity of the ball before it reaches the ground.
Calculate the velocity of the ball before it reaches the ground.
Answers
Arora
Change in potential energy = Kinetic Energy
m*g*h = (1/2)*m*(v^2)
9.8 * 2.5 * 2 = v^2
49 = v^2
v = 7 m/s
m*g*h = (1/2)*m*(v^2)
9.8 * 2.5 * 2 = v^2
49 = v^2
v = 7 m/s
Henry
V^2 = Vo^2 + 2g*h = 0 + 19.6*2.5 = 49,
V = 7 m/s.
V = 7 m/s.