Asked by Brittany
a 0.67 kg rubber ball has a speed of 2.2 m/s at point a and kinetic energy 7.1 J at point B find the total work done on the ball as it moves from a to b
Answers
Answered by
Elena
W=KE2-KE1=KE2 - mv²/2=
=7.14 - 0.67•2.2²/2 = 5.52 J
=7.14 - 0.67•2.2²/2 = 5.52 J
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