Asked by Davone

A rubber ball is dropped from the top of a hole.Exactly 3.0 seconds later, the sound of the rubber ball hitting bottom is heard.How deep is the hole?
HInt:- The distance that dropped object falls in t sec is represented by the formula s = 16t^2.The speed of sound is 1100 ft/sec

Answers

Answered by Steve
If the hole has depth h, then

√h/4 + h/1100 = 3.0
h = 132'8"
Answered by Zion
What if the time was 3.5 seconds
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