Asked by Sam
a rubber ball is dropped from a height of 5m. After the 5th bounce, the ball only comes back up to 0.76m in height/ Find the percentage loss of kinetic energy for each individual bounce.
Answers
Answered by
drwls
Let r be the fraction of kinetic energy left after a single bounce. Thatequals the height ratio for each pair of successive bounces, which is proportional to the recovered kinetic energy ratio. The ratio is called the coefficient of restitution.
H (after fifth bounce)/Ho = r^5 = 0.76/5 = 0.152
r = (0.152)^0.2 = 0.686
H (after fifth bounce)/Ho = r^5 = 0.76/5 = 0.152
r = (0.152)^0.2 = 0.686
Answered by
Sam
oh thank you so much; I was still trying to figure this out! :D
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