A balloon inflated in a room at 24°C has a volume of 4.00 L. The ballon is then heated to a temperature of 58°C. What is the new volume if the pressure remains constant ?

Answer 1

V1/T1=V2/T24.00/24=X/584.00*58=24*X232/24=X _X=9.6 L

Answer 2

V1/T1=V2/T
24.00/24=X/58
4.00*58=24*X
232/24=X
X=9.6 L

Answer 3

I advise using degrees Kelvin
T1 = 273 + 24 = 297 K
T2 = 273 + 58 = 331
so
V2 = V1 ( T2/T1) = 4 (331/297) = 4.46 Liters

Answer 4

Anonymous is right on. Kelvin is the way to go.