Rate of increase:
dV / dt = 10
dV = 10 dt
Integrating both sides:
V = 10 t + C
C = integration constant
Initial condition:
t = 0 , V = 1
V = 10 t + C
1 = 10 ∙ 0 + C
1 = 0 + C
1 = C
C = 1
V = 10 t + C
V = 10 t + 1
After 3 seconds:
V = 10 ∙ 3 + 1
V = 31 cm³
A balloon is inflated so that its increase in volume is at a constant rate of 10cm^3 s^-1. If its volume is initially 1 cm^3, find its volume after 3 seconds.
Answer: 31 cm^3
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