Asked by me
A balloon is being inflated,the radius of the balloon,initially zero,increases at the rate of 9 ft/sec.How fast is the volume increasing after 1/2 second?
Answers
Answered by
Reiny
V = (4/3) π r^3
dV/dt = 4πr^2 dr/dt
after 1/2 second, the radius is 4.5 ft
back in dV/dt
= 4π(4.5)^2 (9) = ....
dV/dt = 4πr^2 dr/dt
after 1/2 second, the radius is 4.5 ft
back in dV/dt
= 4π(4.5)^2 (9) = ....
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.