Asked by Aggie123
A spherical balloon is inflated so that its volume is increasing at the rate of 3.2 ft3/min. How rapidly is the diameter of the balloon increasing when the diameter is 1.2 feet?
Answers
Answered by
Reiny
V = (4/3)π r^3
dV/dt = 4π r^2 dr/dt
when r = .6 , dV/dt = 3.2
3.2 = 4π(.6)^2 dr/dt
dr/dt = 3.2/(1.44π) = appr .707
so d(diameter)/dt = 1.415 ft/min
dV/dt = 4π r^2 dr/dt
when r = .6 , dV/dt = 3.2
3.2 = 4π(.6)^2 dr/dt
dr/dt = 3.2/(1.44π) = appr .707
so d(diameter)/dt = 1.415 ft/min
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.