Asked by Molly
A spherical balloon is inflated at the rate of 5 cubic feet/minute. What is the volume of the balloon if when the radius is increasing at the rate of 3 feet/minute?
Answers
Answered by
Damon
dV = surface area * dr
for a sphere
dV = 4 pi r^2 dr
dV/dt = 4 pi r^2 dr/dt
5 = 4 pi r^2 (3)
r^2 = 5/(12 pi)
for a sphere
dV = 4 pi r^2 dr
dV/dt = 4 pi r^2 dr/dt
5 = 4 pi r^2 (3)
r^2 = 5/(12 pi)
Answered by
bobpursley
Volume=4/3 PI r^3
dV/dt=5=4 PI r^2 dr/dt
you are given dr/dt = 3ft/min
and dv/dt=5ft^3/min
solve for r, and then calculate V
dV/dt=5=4 PI r^2 dr/dt
you are given dr/dt = 3ft/min
and dv/dt=5ft^3/min
solve for r, and then calculate V
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