Asked by Candice
A weather balloon is inflated to a volume of 25.6L at a pressure of 736mmHg and a temperature of 31.9∘C. The balloon rises in the atmosphere to an altitude, where the pressure is 365mmHg and the temperature is -15.6∘C.
Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.
Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.
Answers
Answered by
Candice
The answer I got is 61.1 L but this is not correct. I do not understand what I am doing wrong.
Answered by
DrBob222
Why didn't you show your work. Then we could find the trouble in an instant.
Use (P1V1/T1) = (P2V2/T2) and remember T must be in kelvin.
Use (P1V1/T1) = (P2V2/T2) and remember T must be in kelvin.
Answered by
Candice
That is the equation that I used.
P1V1T2/T1P2 = (736mmHg x 25.6 L x 304.9 K)/(365mmHg x 257.4K) = 61.1 L
P1V1T2/T1P2 = (736mmHg x 25.6 L x 304.9 K)/(365mmHg x 257.4K) = 61.1 L
Answered by
Jan
You forgot to change the units of P from mmHg to atm. To do this, just divide the mmHg value by 760 mmHg/atm.
Answered by
Candice
I've tried it by changing mmHg to atm and I still get 61.1L
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