Question
solve the logarithm equation log2(x^2-2x+5)=2
Answers
mathhelper
log2(x^2-2x+5)=2
x^2 - 2x + 5 = 2^2 by definition
x^2 - 2x + 1 = 0
(x - 1)^2 = 0
x - 1 = 0
x = 1
x^2 - 2x + 5 = 2^2 by definition
x^2 - 2x + 1 = 0
(x - 1)^2 = 0
x - 1 = 0
x = 1