Asked by Benedicta
solve the logarithm equation log2(x^2-2x+5)=2
Answers
Answered by
mathhelper
log2(x^2-2x+5)=2
x^2 - 2x + 5 = 2^2 by definition
x^2 - 2x + 1 = 0
(x - 1)^2 = 0
x - 1 = 0
x = 1
x^2 - 2x + 5 = 2^2 by definition
x^2 - 2x + 1 = 0
(x - 1)^2 = 0
x - 1 = 0
x = 1
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