Asked by Armando
Solve the following logarithm equation. Please show all of your work.
log (5 + x) – log(x – 2) = log 2
log (5 + x) – log(x – 2) = log 2
Answers
Answered by
Reiny
log (5 + x) – log(x – 2) = log 2
log [(5+x)/(x-2)] = log 2
(5+x)/(x-2) = 2
2x - 4 = 5+x
x = 9
log [(5+x)/(x-2)] = log 2
(5+x)/(x-2) = 2
2x - 4 = 5+x
x = 9
Answered by
MathMate
Use law of logarithms,
log(a)-log(b)=log(a/b)
So
log (5 + x) – log(x – 2) = log 2
=log((5+x)/(x-2))=log2
Take anti-log on both sides
(5-x)/(x-2)=2
(5-x)=2(x-2)
Solve for x.
log(a)-log(b)=log(a/b)
So
log (5 + x) – log(x – 2) = log 2
=log((5+x)/(x-2))=log2
Take anti-log on both sides
(5-x)/(x-2)=2
(5-x)=2(x-2)
Solve for x.
Answered by
Bosnian
(5+x)/(x-2)=2
5+x=2*(x-2)
5+x=2x-4
5+4=2x-x
9=x
x=9
5+x=2*(x-2)
5+x=2x-4
5+4=2x-x
9=x
x=9
Answered by
Anonymous
−6ln(x) − 8ln(y) +
1
8
ln(z)
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