Question
Writ the equation in Logarithm form
25=(1/5)^2
a=b^c
25=(1/5)^2
a=b^c
Answers
Kuai
Logb(a) = c
Log1/5(25) = 2
Log1/5(25) = 2
Steve
but 25 is not (1/5)^2
(1/5)^2 = 1/25
25 = 1/(1/5)^2 = (1/5)^-2
So, log<sub>1/5</sub>25 = -2
loga = c*logb
regardless of base. Using b for the base, log_b(b)=1,so
log<sub>b</sub>a = c
(1/5)^2 = 1/25
25 = 1/(1/5)^2 = (1/5)^-2
So, log<sub>1/5</sub>25 = -2
loga = c*logb
regardless of base. Using b for the base, log_b(b)=1,so
log<sub>b</sub>a = c