Question

A baseball is thrown upward at an initial speed of 9.5 m/s. The approximate height of the ball, h meters, after t seconds, is given by the equation h= -4.9t+9.5t+1. At the same time, a golf ball is hit upward at an initial speed of 12 m/s. The approximate height of the ball, h meters, after t second, is given by the equation h=-4.9t^2+12t. When are both balls at the same height? Round to the nearest tenth.

Answer 1

At the same height when
-4.9t^2+12t = -4.9t+9.5t+1
2.5t = 1
t = 1/2.5 = .4 seconds