Question

A baseball is thrown upward from ground level with an initial velocity of 48 feet per second, and its height h in feet is given by , where t is the time in seconds.
At what time does the ball reach 10 feet? Round to the nearest tenth.

Step by step please

Answer 1

h(t) = 48t - 16t^2
so, plug in 10 for h and solve for t:

10 = 48t - 16t^2
8t^2 - 24t + 5 = 0
t = (6±√26)/4
or
t=0.225s (on the way up)
t=2.774s (on the way back down)